geof_junk Posted December 29, 2020 Share Posted December 29, 2020 In 1980 I had to work out the formula myself, no internet. The photo of my note book is a bit poor, but the detail is there. 4 Link to comment Share on other sites More sharing options...
Johnno481 Posted December 29, 2020 Share Posted December 29, 2020 I used the formula I have used for 40 years and always found pretty accurate. It is as follows; air weight = 125.8. Water weight = 100.3 Air weight minus water weight gives the cubic cms of volume of 25.5. Air weight divided by the cubic cms of volume gives the specific gravity of 4.93. Then using the equation of 116 - 310 divided by the SG of 4.93 gives a figure of 53.12, which is the percentage of gold in the specimen. Which comes in at 66.82 gms. Quite close to the melted weight of 66.2 gms. 7 Link to comment Share on other sites More sharing options...
Gold Catcher Posted December 29, 2020 Share Posted December 29, 2020 Amazing JP! I am glad I was off 😁🤑 2 Link to comment Share on other sites More sharing options...
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