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Solution :

The mass of an `H_(2)` molecule may be calculated from the molecule weight as <br> `m = (M)/(N_(0)) = (2.016 xx 10^(-3) kg//mol)/(6.02 xx 10^(23) mol^(-1)) = 3.35 xx 10^(-27) kg` <br> Then `(1)/(2) mv_(rms)^(2) = (3)/(2) kT` <br> `v_(rms) = sqrt((3 kT)/(m)) = sqrt((3(1.38 xx 10^(-23))(373.15))/(3.35 xx 10^(-27))) = 2.15 km//s`